The normalization formula adopted by the NITs for 2013 admissions

Suppose

· A₀ is the aggregate score of a student in JEE-Main;

· B₀ is the percentage score of that student in the Class XII Board examination, and P is the corresponding percentile rank.

(Recall that the percentile rank of a student is the percentage of fellow students with score below the score of that student.)

Suppose

· B₁ is that aggregate score in JEE-Main, which corresponds to the percentile P among all JEE-Main candidates;

· B₂ is that aggregate score in JEE-Main, which corresponds to the percentile P among all JEE-Main candidates from the Board of the concerned student.

Linear interpolation may be used, where necessary, to compute B₁ and B₂ from P. Then, according to the normalization formula adopted by JIG,

· the normalized Board score of the student is B_final = 0.5*(B₁ + B₂), and

· the composite score of the student is C = 0.6*A₀ + 0.4*B_final. This is the score used for preparing the merit list.

The scores B₁ and B₂ are computed from B₀ by using the relation between the scores and the percentiles, for three sets of scores:

· the set of Class XII Board scores (including B₀) for the Board of the student concerned;

· the set of JEE-Main scores of all candidates;

· the set of JEE-Main scores of all candidates from the Board of the student concerned.

The percentile-to-score relation of the first and the third set vary from Board to Board. This is illustrated through the accompanying figure.

It is seen that a common percentile P in the two different Boards leads to the same value of B₁ but different values of B₂.

The Joshi Committee, with support from ISI, had recommended the use of B₁ alone as the normalized Board score.

The Chairman-CBSE had promoted the use of B₂ alone as the normalized Board score.

The following is a selected part of a hypothetical example given in a newspaper article to illustrate the normalization procedure.